不定積分の ∫ 1 - sin²x dx = -1 - tanx
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posted:ヌマゴン[lKsvH4n83nww10] 13/12/01 14:31:27
comment:
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∫{1}over{sin^2 x}dx
newline =∫{(sin^2 x+cos^2 x)}over{sin^2 x} dx
newline =∫{sinx sinx+cosx cosx}over{sin^2 x} dx
newline =∫{-(cosx)'sinx+cosx(sinx)'}over{sin^2 x} dx
newline =-∫{(cosx)'sinx-cosx(sinx)'}over{sin^2 x} dx
newline =-∫({cosx}over{sinx})' dx
newline =-{cosx}over{sinx} +C
newline =-{1}over{tanx} +C
文にするとこんな感じ....
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何の擬人化でしょう?
posted:ジャンボ
comment:
正解は↓にあります
正解は[イギリ...
健全ロボ アマミダラーw
posted:ドルジ
comment:
アイマスネタ貼りw
よし!私が乗るとしよう(´∀`)
そして右の娘は誰かなw...
あんぱん男
posted:ジャンボ
comment:
だが、断る!!
心のセールスマン
posted:ジャンボ
comment:
[喪黒&QB]のコンビか…(-ω-;)
進撃の巨人
posted:コウ
comment:
え?実写?
勘弁してくれ…( ´△`)
境ホラ
posted:ジャンボ
comment:
黄金の右か!!Σ( ̄□ ̄;)
Bulletin board
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1:No name[cAv00G4eOaA.16] 13/12/01 16:06:39
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理系なら常識
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2:No name[K3V6HNTV4obT01] 13/12/01 16:27:18
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分からなすぎて文字化けしてるのかと思った…
これ、高校でやるの?
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3:本物[cTLFPoYYs7Vf01] 13/12/01 19:18:46
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彼のクラスメイトです
数学教師の無茶ぶりで自分で調べろ言われまして…
な?偽物
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4:ヌマゴン(偽者)[lKsvH4n83nww10] 13/12/02 11:58:13
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な?と言われても困るんだが....
まあ、なんのためにUPしたのかと言うと
この公式をばら撒きまくって
間違っていたらだれかが訂正してくれるだろう。
という考えでUPしたので
常識と返って来るということは
この公式は正解ということですかね。
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5:本物[cTLFPoYYs7Vf01] 13/12/02 12:35:57
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正解なんかな?
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6:georgia[jdewNEOF08zg16] 13/12/02 14:25:44
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俺みたいなバカには暗号にしか見えない…
こんな数式見てたら眠くなる
1
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